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limx 0sin3x sin5x

求极限limx-0sin3x/sin5xlimx-0 sin3x/sin5x=limx-0 [(sin3x/3x)*3x]/[(sin5x/5x)/5x]=limx-0 [(

limsin3x/sin5x(当x趋于0时)lim(x→0)(sin3x)/(5x)=lim(x→0)(3cos3x)/5 =3/5 =0.6

【limx趋近于0(tan3x/sin5x)求极限?我有结果.】方法一:本题最简单的方法是等价无穷小代换tan3x等价于3x,sin5x等价于5x,因此lim[x→0]

limx趋近于0时, sin3x/sin5x=??回答:=3x/5x=3/5(等价无穷小)

求极限limx-0 sin3x/sin5x/5x]=3/5limx-0[ (sin3x/3x)/(sin5x/5x)]=3/5[limx-0 (sin3x/3x)]/[limx-0 (sin5x/5x)]=3/5*1/2=3

limx→0sin3x/sin5x,求极限lim sin3x/sin5x =lim 3x/(5x)=3/5 当x趋于0时,sin3x等价于3x,sin5x等价于5x

limx→0sin3x/sin5x能不能化简到重要极限limx→0sinx/运用等价无穷小,sin3x~3x,sin5x~5X,所以原式等于limx→0 3x/5x,这是0/0未定式,运用

lim x趋向于0tan3x/sin5x回答:要记住在x 趋于0的时候, sinx,tanx等等都是等价于x的, 那么在这里, tan3x等价于3x,sin5x等价于5x 所以 原极限 =lim(x

lim x趋近于0(tan3x/sin5x) 求极限???求解答过程。我有结果方法二:如果没学过等价无穷小代换,就用重要极限 lim[x→0] tan3x/sin5x =lim[x→0] (3/5)[tan3x/(3x)][5x/sin5x

lim(x趋于0)sin5x-sin3x/sinx=不能用等价无穷小,虽然有些时候答案对。

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